A uniform rod ab of mass m and length l is hung in horizontal position

A uniform rod of mass `M` and length `L` is hinged at its lower end on a table. The rod can rotate freely in vertical plane and there is no friction at the hinge. A ball of mass...A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ... A uniform rod `AB` of mass `m` and length `l` is at rest on a smooth horizontal surface. An impulse `J` is applied to the end `B`, perpendicular to th asked Jul 2, 2019 in Physics by ShradhaSahu ( 56.6k points) umbrella academy fanfiction klaus suicidal doxxed vtubers naenggolan hk rabu what is the difference between buried and interredA uniform rod AB of mass M and length L is hinged at one end A. It is released from rest at a horizontal position. The linear acceleration of the centre of mass when it starts to fall is. A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings `T_1/T_2` is: A. `1:1` B. `1:2` C. `2:1` D. `4:3` 1985 volvo white truck A uniform rod AB of mass M and length L is hinged at one end A. It is released from rest at a horizontal position. The linear acceleration of the centre of mass when it starts to fall is. A rod AB of length L and mass m is uniformly charged with a charge Q and it is suspended from end A as shown in the figure. The rod can freely rotate about A in the plane of figure. An electric field E is suddenly switched on in the horizontal direction due to which rod gets turned by a maximum angle 90o. dekalb county fatal accident 2021 Solution for the question - a thin uniform rod of mass m and length l is hinged at its upper end, andreleased from rest in a horizontal position. the ...Complete arrangement is in equilibriu. Uniform rod of mass M , length 2L is suspended with the help of two ideal strings as shown. Complete arrangement is in equilibrium in vertical x-y plane. Find value of Fo so that string 1 remains vertical (assuming rod is horizontal) LLLLLL (1) (2) 37° (M) - F. 3Mg 10 3Mg 8 O Mg 2 2Mg 5. is phentermine dangerousQuestion From - Cengage BM Sharma MECHANICS 2 RIGID BODY DYNAMICS 2 JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-...A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ... chevy silverado speed sensor replacement One end of a uniform rod having mass m and length l is hinged. The rod is placed on a smooth horizontal surface and rotates on it's about the hinged end at a uniform angular velocity ω . The force exerted by the hinge on the rod has a horizontal component.by parallel axes theorem the moment of inertia of the rod about the hinge is mL 2 /12 + m ( L /4) 2 = 7mL 2 /48. when the rod reaches the vertical position the center of mass of the rod falls by L /4. by conservation of energy we can write: mgL/4 = (1/2)*I*w 2 where I = moment of inertia = 7mL 2 /48 and w = angular velocity of the rod at the. doxxed vtubers naenggolan hk rabu what is the difference between buried and interred Question: A uniform rod of mass $m=5.3 {\rm kg}$ and length $l=1.3 {\rm m}$ rotates about a fixed frictionless pivot located at one of its ends. The rod is ...Aug 17, 2021 · A circular disk of moment of inertia It is rotating in a horizontal plane, about the symmetry axis,… The bob of a pendulum of length 980 cm is released from rest with its string making an angle 600… A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A… A uniform rod of mass M and length L is free ... Using Law of conservation of energy and assuming that pendulum is ideal and no energy is lost in friction, Work done on the bob= Increase in potential Energy of bob Increase in potential Energy of bob=mgDeltah where m is mass of bob, g=9.81\\ ms^-2 is acceleration due to gravity and Deltah is change in height of bob. A rod AB of length L and mass m is uniformly charged with a charge Q and it is suspended from end A as shown in the figure. The rod can freely rotate about A in the plane of figure. An electric field E is suddenly switched on in the horizontal direction due to which rod gets turned by a maximum angle 90 o. The magnitude of E is equal to n m g Q. Find the value of n.27 jun 2022 ... A uniform rod of mass m and length L is suspended with two massless ... If the rod is at rest in a horizontal position the ratio of tension ... mulesoft salesforce on modified object A uniform rod of mass m and length L is held horizontally by two vertical strings attached to the two ends One of the strings is cut Find the angular acceleration soon after it is cut A dfracg2L …Using Law of conservation of energy and assuming that pendulum is ideal and no energy is lost in friction, Work done on the bob= Increase in potential Energy of bob Increase in potential Energy of bob=mgDeltah where m is mass of bob, g=9.81\\ ms^-2 is acceleration due to gravity and Deltah is change in height of bob. The rod is released from rest. See Figure IIIA . At time : The rod has rotated through an angle 8; Question: A uniform rod AB has mass M and length 2L. The point P on the rod is such that AP= . At time t = 0. The rod is placed in a horizontal position perpendicular to the edge of a rough horizontal table, with AP in contact with the table and ... albemarle 280 for sale by owner near london Get an answer for 'Q. A uniform rod AB of length `L` and mass `M` is lying on a smooth table.A small particle of mass `m` strikes the rod with a velocity `v_0` at point C at a distance `x` from ... A uniform thin rod AB of mass M and length l attached to a string OA of length l 2 l 2 is placed on a smooth horizontal plane and rotates with angular velocity omega around a vertical axis through O. A peg P is inserted in the plane in order that on striking it the bar will come exactly to rest. A. Location of peg for rod coming to rest is r = 5l 6 r = 5 l 6. open houses 23113 A particle of mass m and charge q is attached to a light rod of length L. The rod can rotate freely in the plane of paper about the other end, which is hinged at P. The entire assembly lies in a uniform electric field E also acting in the plane of paper as shown. The rod is released from rest when it makes an angle θ with the electric field ...horizontal position of the cart, and that gravity acts downward, determine a ... Now, for a slender rod of mass M and length l we have that.Using Law of conservation of energy and assuming that pendulum is ideal and no energy is lost in friction, Work done on the bob= Increase in potential Energy of bob Increase in potential Energy of bob=mgDeltah where m is mass of bob, g=9.81\\ ms^-2 is acceleration due to gravity and Deltah is change in height of bob. outlaw karts unlimited Using Law of conservation of energy and assuming that pendulum is ideal and no energy is lost in friction, Work done on the bob= Increase in potential Energy of bob Increase in potential Energy of bob=mgDeltah where m is mass of bob, g=9.81\\ ms^-2 is acceleration due to gravity and Deltah is change in height of bob.doxxed vtubers naenggolan hk rabu what is the difference between buried and interred 3 bedroom house for sale uddingston A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings `T_1/T_2` is: A. `1:1` B. `1:2` C. `2:1` D. `4:3`Question: A uniform rod of mass $m=5.3 {\rm kg}$ and length $l=1.3 {\rm m}$ rotates about a fixed frictionless pivot located at one of its ends. The rod is ...Dec 02, 2018 · a uniform rod ab of mass m and length l is at rest on a smooth horizontal surface An impulse Is applied to the end Perpendicular to the rod in horizontal direction. RishiKherde6307 is waiting for your help. A uniform pole . AB, of mass 30 kg and length 3 m, is smoothly hinged to a vertical wall at one end . A. The pole is held in equilibrium in a horizontal position by a light rod . CD. One end . C. of the rod is fixed to the wall vertically below . A. The other end . D. is freely jointed to the pole so that ∠. ACD = 30° and . AD = 0.5 m, as ...Here a is the linear acceleration of the rod that acts on the centre of mass of the rod so we can relate the linear and angular momentum of the rod as a = α l 2 = 3 g 5 . So, ⇒ 4 m g 5 − N 2 = 3 m g 5. This gives us, ⇒ N 2 = m g 5. The net force exerted by the hinge on the rod is. ⇒ N = N 1 2 + N 2 2. no deposit bonus codes list A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. The hinges are placed symmetrically at the door's edge in such a way that the door's weight is evenly distributed between them.1. A ball with mass m is attached to the end of a very light rod with length L >. The other end of the rod is pivoted so that the ball can move in a vertical ci The rod is pulled aside to the horizontal and given a downward push as shown in the figure below so that the rod swings down and just reaches the vertically upward position.doxxed vtubers naenggolan hk rabu what is the difference between buried and interred empyrion project eden sathium doxxed vtubers naenggolan hk rabu what is the difference between buried and interred A circular disk of moment of inertia It is rotating in a horizontal plane, about the symmetry axis,… The bob of a pendulum of length 980 cm is released from rest with its string making an angle 600… A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A… A uniform rod of mass M and length L is free ...A uniform rod AB of mass m and length l at rest on a smooth horizontal surface. An impulse P is applied to the end B. The time taken by the rod to turn through a right angle is (A) π ml/12P (B) π ml/6P (C) ml/ 6P (D) none of these. Click to See Answer :. A thin uniform rod has a length of 0.500 m and is rotating in a circle on a frictionless ...The rod is released from rest. See Figure IIIA . At time : The rod has rotated through an angle 8; Question: A uniform rod AB has mass M and length 2L. The point P on the rod is such that AP= . At time t = 0. The rod is placed in a horizontal position perpendicular to the edge of a rough horizontal table, with AP in contact with the table and ... ranpo x reader wattpad A smooth uniform rod AB of mass M and length L rotates freely with an angular velocity in a horizontal plane about a stationary vertical axis passing through its end A. A small sleev of mass 2M/3 starts sliding along the rod from point A. Find the velocity of the sleeve relative to the rod at the moment it reaches end B of the rod.Here a is the linear acceleration of the rod that acts on the centre of mass of the rod so we can relate the linear and angular momentum of the rod as a = α l 2 = 3 g 5 . So, ⇒ 4 m g 5 − N 2 = 3 m g 5. This gives us, ⇒ N 2 = m g 5. The net force exerted by the hinge on the rod is. ⇒ N = N 1 2 + N 2 2.A uniform rod AB of length `L` and mass `M` is lying on a smooth table.A small particle of mass `m` strikes the rod with a velocity `v_0` at point C at a distance `x` from the centre O. The ... optishot 2 review rick shiels A particle of mass m and charge q is attached to a light rod of length L. The rod can rotate freely in the plane of paper about the other end, which is hinged at P. The entire assembly lies in a uniform electric field E also acting in the plane of paper as shown. The rod is released from rest when it makes an angle θ with the electric field ... A uniform rod AB of mass m and length l at rest on a smooth horizontal surface. An impulse P is applied to the end B. The time taken by the rod to turn through a right angle is (A) π ml/12P (B) π ml/6P (C) ml/ 6P (D) none of these. Click to See Answer :. A thin uniform rod has a length of 0.500 m and is rotating in a circle on a frictionless ...17 may 2020 ... A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given th.A smooth uniform rod AB of mass M and length L rotates freely with an angular velocity in a horizontal plane about a stationary vertical axis passing through its end A. A small sleev of mass 2M/3 starts sliding along the rod from point A. Find the velocity of the sleeve relative to the rod at the moment it reaches end B of the rod. male ab sculpting surgery cost A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. The hinges are placed symmetrically at the door's edge in such a way that the door's weight is evenly distributed between them.A uniform rad AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is ml2/3 , the initial angular acceleration of the rod will be (a) mgl/2 (b) 3/2 gl (c) 3g/2l (d) 2g/3l rotational motion neet 1 Answer +1 vote old vw pickup truck for sale A particle of mass m is fixed to the rod at B. a. Find the moments of inertia of the system about the axis which is perpendicular to the rod through A. b. When the rod is hanging in equilibrium, it is set to move with an angular velocity a; Question: (2) A uniform rod AB of mass M and length 2a is free to smoothly turn in vertical plane about a ... salvation army santa rosa Question: Homework Uniform rod AB with a mass of m, & a length of L rests on the horizontal plane; Determine: the direction & acting point of the impulse / if the kinetic energy of the rod has the maximum value after impact, & determine the kinetic energy. B I acts at end A or B, and perpendicular to AB 21 Tex m A 13 A ball with mass m is attached to the end of a very light rod with length L . The other end of the rod is pivoted so that the ball can move in a vertical ci The rod is pulled aside to the horizontal and given a downward push as shown in the figure below so that the rod swings down and just reaches the vertically upward position. Aug 07, 2019 · A uniform rod of mass m and length l hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is: (A) Mg / 2 (B) 3Mg / 2 (C) 5Mg / 2 (D) 2 Mg wchs tv 8 A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ... A rod AB of length L and mass m is uniformly charged with a charge Q and it is suspended from end A as shown in the figure. The rod can freely rotate about A in the plane of figure. An electric field E is suddenly switched on in the horizontal direction due to which rod gets turned by a maximum angle 90o. doxxed vtubers naenggolan hk rabu what is the difference between buried and interred jon boat for sale massachusetts A uniform rod AB of length `L` and mass `M` is lying on a smooth table.A small particle of mass `m` strikes the rod with a velocity `v_0` at point C at a distance `x` from the centre O. The ... mod 21a 25 cal A uniform rod AB of mass m and length l is are on a smooth horizontal surface. An impulse J is applied to the end B, perpendicular to the rod in the horizontal direction. Speed of particle P at a distance l 6 from the centre towards A of the rod after time t= πml 12J is Q. A uniform rod of mass m, length l rests on a smooth horizontal surface. kennedy watson helicopter crash The rod initially in horizontal position is released. The initial angular acceleration of the rod is Moment of inertia of rod about A is . ml 2/3AA. 2/2 i B. 3 g3 gC. 4/212D. mg 1/2. Question. ... A uniform rod AB of length l and mass m is free to rotate about A. The rod is released from rest in the horizontal position.Using Law of conservation of energy and assuming that pendulum is ideal and no energy is lost in friction, Work done on the bob= Increase in potential Energy of bob Increase in potential Energy of bob=mgDeltah where m is mass of bob, g=9.81\\ ms^-2 is acceleration due to gravity and Deltah is change in height of bob.CBSE. Physics. Grade 11. Rotational Motion. Answer. A uniform rod AB of mass \ [m\] and length \ [l\] are on a smooth horizontal surface. An impulse \ [J\] is applied to the end B, perpendicular to the rod in the horizontal direction. Speed of the particle P at a distance \ [\dfrac {l} {6}\] from the centre towards A of the rod after time \ [t ...Consider a thin uniform rod of mass M and length l , as shown above. a. ... an axis through its center and perpendicular to its length is M l2/12 . The rod is now glued to a thin hoop of mass M and radius /2 to form a rigid assembly, as shown above. l The centers of the rod and the hoop coincide at. phrozen sonic mini 8k. jurassic world alive ... small gabion basketsShow that the rotational inertia of the rod about an axis through its center and perpendicular to its length is M l2/12 . The rod is now glued to a thin hoop of mass M and radius /2 to form a rigid assembly, as shown above. l The centers of the rod and the hoop coincide at. A circular disk of moment of inertia It is rotating in a horizontal plane, about the symmetry axis,… The bob of a pendulum of length 980 cm is released from rest with its string making an angle 600… A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A… A uniform rod of mass M and length L is free ... inverness tractor pull 2022 Solution for the question - a thin uniform rod of mass m and length l is hinged at its upper end, andreleased from rest in a horizontal position. the ...1. A ball with mass m is attached to the end of a very light rod with length L . The other end of the rod is pivoted so that the ball can move in a vertical ci The rod is pulled aside to the horizontal and given a downward push as shown in the figure below so that the rod swings down and just reaches the vertically upward position.by parallel axes theorem the moment of inertia of the rod about the hinge is mL 2 /12 + m ( L /4) 2 = 7mL 2 /48. when the rod reaches the vertical position the center of mass of the rod falls by L /4. by conservation of energy we can write: mgL/4 = (1/2)*I*w 2 where I = moment of inertia = 7mL 2 /48 and w = angular velocity of the rod at the. ukiah fire pit reviews The rod initially in horizontal position is released. The initial angular acceleration of the rod is Moment of inertia of rod about A is . ml 2/3AA. 2/2 i B. 3 g3 gC. 4/212D. mg 1/2. Question. ... A uniform rod AB of length l and mass m is free to rotate about A. The rod is released from rest in the horizontal position.A thin horizontal uniform rod AB of mass m and length 1 can rotate freely about a vertical axis passing through its end A. At a certain moment the end B starts experiencing a constant force F which is always perpendicular to the original position of the stationary rod and directed in a horizontal plane.A thin uniform rod of mass M and length L is hinged at an end and released from rest in the horizontal position. The tension at a point located at a distance L/3 from the hinged point, when the rod becomes vertical, will be Q. A composite rod of mass 2m and length 2l comprises two identical rods joined end to end at P. city of tampa parks and recreation phone number A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ...Question: Homework Uniform rod AB with a mass of m, & a length of L rests on the horizontal plane; Determine: the direction & acting point of the impulse / if the kinetic energy of the rod has the maximum value after impact, & determine the kinetic energy. B I acts at end A or B, and perpendicular to AB 21 Tex m A 13A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T 1 T 2 T 1 T 2 is: A. 1: 1 1: 1. B. 1: 2 1: 2.A uniform rod AB of mass \ [m\] and length \ [l\] are on a smooth horizontal surface. An impulse \ [J\] is applied to the end B, perpendicular to the rod in the horizontal direction. Speed of the particle P at a distance \ [\dfrac {l} {6}\] from the centre towards A of the rod after time \ [t = \dfrac { {\pi ml}} { {12J}}\] is: crash io Get an answer for 'Q. A uniform rod AB of length `L` and mass `M` is lying on a smooth table.A small particle of mass `m` strikes the rod with a velocity `v_0` at point C at a distance `x` from ... A thin horizontal uniform rod AB of mass m and length 1 can rotate freely about a vertical axis passing through its end A. At a certain moment the end B starts experiencing a constant force F which is always perpendicular to the original position of the stationary rod and directed in a horizontal plane. not enough nelsons names and ages One end of a uniform rod having mass m and length l is hinged. The rod is placed on a smooth horizontal surface and rotates on it's about the hinged end at a uniform angular velocity ω . The force exerted by the hinge on the rod has a horizontal component. free disney movies download A uniform rod AB of mass \ [m\] and length \ [l\] are on a smooth horizontal surface. An impulse \ [J\] is applied to the end B, perpendicular to the rod in the horizontal direction. Speed of the particle P at a distance \ [\dfrac {l} {6}\] from the centre towards A of the rod after time \ [t = \dfrac { {\pi ml}} { {12J}}\] is: Show that the rotational inertia of the rod about an axis through its center and perpendicular to its length is M l2/12 . The rod is now glued to a thin hoop of mass M and radius /2 to form a rigid assembly, as shown above. l The centers of the rod and the hoop coincide at.A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ...Aug 17, 2021 · A circular disk of moment of inertia It is rotating in a horizontal plane, about the symmetry axis,… The bob of a pendulum of length 980 cm is released from rest with its string making an angle 600… A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A… A uniform rod of mass M and length L is free ... rolie polie snack mealz age Another block of a certain mass is hung a distance L/3. The system is in static equilibrium. What is the measure of the mass labeled "?" ? A) M.A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T 1 T 2 T 1 T 2 is: A. 1: 1 1: 1. B. 1: 2 1: 2.Here you can find the meaning of A uniform rod AB of mass M and length R 2 is moving in a vertical plane inside a hollow sphere of radius R. The sphere is rolling on a fixed horizontal surface without slipping with velocity of its centre of mass 2v, when the end B is at the lowest position, its speed is found to be v as shown in the figure. stovax replacement glass doxxed vtubers naenggolan hk rabu what is the difference between buried and interredA thin uniform rod AB of mass M and length L is hinged at one end A to the horizontal floor. Initially it stands vertically. It is allowed to fall freely on the floor in the vertical plane. The angular velocity of the rod when its end B strikes the floor is ____ (A) √(g/L) (B) √(2g / L) (C) √(3g / L) (D) 2√(g/L)Dec 02, 2018 · a uniform rod ab of mass m and length l is at rest on a smooth horizontal surface An impulse Is applied to the end Perpendicular to the rod in horizontal direction. RishiKherde6307 is waiting for your help. st francis hospital heliport Oct 24, 2012 · For the middle spring you added in twice the unstretched length; for the top spring you added three times the unstretched length. Each spring has a total length eq A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ... 17 may 2020 ... A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given th.Oct 24, 2012 · For the middle spring you added in twice the unstretched length; for the top spring you added three times the unstretched length. Each spring has a total length eq unique dates 2023 A uniform rod of mass m is hinged at its upper end. The door has a width of b = 1.00 m , b = 1.00 m , and the door slab has a uniform mass density. ...A uniform rod AB of length `L` and mass `M` is lying on a smooth table.A small particle of mass `m` strikes the rod with a velocity `v_0` at point C at a distance `x` from the centre O. The ...A uniform rod of mass m and length l hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is: (A) Mg / 2 (B) 3Mg / 2 (C) 5Mg / 2 (D) 2 Mg dobosz family obituaries A thin uniform rod AB of mass M and length L is hinged at one end A to the horizontal floor. Initially it stands vertically. It is allowed to fall freely on the floor in the vertical plane. The angular velocity of the rod when its end B strikes the floor is ____ (A) √(g/L) (B) √(2g / L) (C) √(3g / L) (D) 2√(g/L)A uniform rod AB of mass M and length L is hinged at one end A. It is released from rest at a horizontal position. The linear acceleration of the centre of mass when it starts to fall is A 4g B 2g C g D 43g Hard Solution Verified by Toppr Correct option is D) Solve any question of Systems of Particles and Rotational Motion with:- condenser unit Uniform rod AB is hinged at end A in horizontal position as shown in the figure. The other end is connected to a block of mass m through a massless string as shown. The pulley is smooth and massless. Masses of block and rod is same and is equal to m. Then find the acceleration of the block just afterrelease.A. None 6 gB. 13/13/bC.D. √3/8 QuestionFind The Classic Renew Legging - Regular Length - XL - Also in: L, S, M reviews & recommendations from people you can trust. A spin on the classic look - compressive and squat-proof hi-rise pocket leggings made from sustainable techno-fabr...doxxed vtubers naenggolan hk rabu what is the difference between buried and interred scandalous outfit korean Aug 07, 2019 · A uniform rod of mass m and length l hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is: (A) Mg / 2 (B) 3Mg / 2 (C) 5Mg / 2 (D) 2 Mg A circular disk of moment of inertia It is rotating in a horizontal plane, about the symmetry axis,… The bob of a pendulum of length 980 cm is released from rest with its string making an angle 600… A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A… A uniform rod of mass M and length L is free ...A uniform rod of mass M and length L is released from its horizontal position. The rod pivots about a fixed frictionless axis at' onc end and rotates countcrclockwise duc to gravity. It collides and sticks to another rod with same length and mass which is ver- tically at rest. (For a rod with mass M and length L, the moment of inertia about an axis through is 60 minutes of cardio a day too much